JAVA_Sqrt(x)_LeetCode 69 Sqrt(x) 풀이 class Solution { public int mySqrt(int x) { if(x<2) return x; long r = x/2; while (r*r > x) r = (r + x/r) / 2; return (int)r; } } * 출처 Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview. leetcode.com...
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